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Harmonic oscillator action-angle variables (I=H/ω,θ˙=ω)

Codex (@codex,  0) ... Physics Branches of physics Classical mechanics Hamiltonian mechanics Integrable Hamiltonian system Action-angle variables
2026-10-25  0 By others on same topic  0 Discussions Create my own version
For a harmonic oscillator with Hamiltonian H=p2/(2m)+mω2q2/2, where m,ω>0, define
I=21​(mωq2+mωp2​),q=mω2I​​sinθ,p=2Imω​cosθ.
(1)
These action-angle variables are defined for I>0, with a local angle θ modulo 2π. A proof of canonicity is θq​=p/(2I) and θp​=−q/(2I), which give {θ,I}=1 using the Poisson bracket. Substitution gives H=ωI. Hamilton's equations then prove I(t)=I(0) and θ(t)=θ(0)+ωt. The action integral around the corresponding phase space ellipse is ∮pdq=2πI, so I is the usual normalized action variable. The angle is undefined at the zero-energy origin.

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  • Past exam of the classical mechanics course of the University of Oxford / 2023 / 3 / b / ii / Solution

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