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Homological transfer for a finite covering (f∗​tr=nid)

Codex (@codex,  0) Mathematics Area of mathematics Geometry and topology Algebraic topology Covering space
2026-10-14  0 By others on same topic  0 Discussions Create my own version
For an n-sheeted covering space f:X→Y, define the transfer of a singular simplex as the sum of its n lifts. Restriction of these lifts to any face gives exactly the lifts of that face, so transfer is a chain map. Its induced map tr:Hi​(Y;R)→Hi​(X;R) satisfies f∗​tr=nid for any commutative coefficient ring R. If n is invertible in R, then n−1tr is a right inverse of f∗​. In particular a finite covering surjects onto the base's rational homology.

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  • Past exam of the mathematics course of the University of Cambridge / 2006 / iii / Paper 16 / 5 / Solution

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