Past exam of the mathematics course of the University of Cambridge 2012 iii Paper 55 2 Solution Created 2026-10-03 Updated 2026-10-07
The topological degree measures an oriented net number of sheets of a map. Its simplest integer-valued setting is a map between connected oriented closed manifolds of the same positive dimension . The hypotheses matter: an integer sign count needs orientations; compactness prevents preimages from escaping; and the same dimension makes a regular fiber discrete. A fundamental class gives the definition for continuous maps:Here and are generated by their chosen fundamental classes. Reversing either orientation changes the sign of the degree of a map between oriented manifolds. Disconnected sources contribute a sum over components; disconnected targets require a degree for each target component rather than one universal integer.
For a smooth map, choose a regular value . The Sard theorem guarantees plentiful choices. Each point of has an invertible derivative, so the inverse function theorem makes it an isolated point. The fiber is finite by compactness of . An oriented coordinate chart defines , and the degree as a sum of local degrees becomesAn empty fiber contributes zero. The sign is independent of the chosen oriented charts. Thus the mapping degree counts sheets with signs, not simply the number of preimages: orientation-preserving and orientation-reversing sheets cancel.
A differential-form argument both proves that this count is independent of and relates it to the topological definition. Around a regular value, take a small neighborhood whose full preimage is a disjoint union of neighborhoods mapped diffeomorphically onto . Compactness rules out additional preimages approaching from elsewhere. Choose a smooth top-degree form supported in , with . The change of variables formula givesAlthough need not be everywhere positive, it represents the same normalized top cohomology class as any normalized volume form. The top de Rham cohomology of a compact connected oriented manifold says that two top forms with equal integrals differ by . Their pullback integrals agree, because the Generalized Stokes theorem gives . Therefore the degree by integration of a pullback volume form isfor every smooth top form . Pairing de Rham cohomology with fundamental classes identifies this integer with the homological definition. This proof also shows that every regular value gives the same signed sum.
The homotopy invariance of mapping degree makes it stable under continuous deformation. Homologically this follows from homotopic maps inducing the same map on homology. For a smooth homotopy , a direct proof uses and the Generalized Stokes theorem on the cylinder to getwith the cylinder orientation chosen to give the indicated boundary signs. Smooth approximation extends the geometric description to continuous maps, while the fundamental class definition already applies without differentiability. The multiplicativity of mapping degree follows from functoriality and givesA constant map has degree zero when . If the mapping degree is nonzero, the map is onto: a point outside its image is a regular value with empty preimage. An orientation-preserving diffeomorphism has degree , and an orientation-reversing one has degree . An orientation-preserving -sheeted covering map has degree ; the signs of sheets must be included for other orientation conventions.
Examples show both the strength and the limits of the invariant. On the circle, has degree , including negative integers and zero; it is the winding number. On the sphere , an ambient reflection has degree , and the antipodal map has degree , because the determinant of on the ambient is . On the torus, an integer matrix induces a map of degree , obtained by pulling back the constant top form. However, degree does not classify general manifold maps: the identity and an integer shear on the two-torus both have degree one but induce different maps on , so are not homotopic.
The mapping degree gives useful obstruction and existence arguments. There is no retraction of a closed ball onto its boundary sphere: such a retraction would make the degree-one identity of the boundary null-homotopic, since it would extend across a contractible ball, contradicting homotopy invariance and the degree-zero constant map. This is the degree obstruction underlying the Brouwer fixed-point theorem. Also an everywhere nonzero tangent vector field on an even-dimensional sphere would, after normalization, produce the homotopy from the identity to the antipodal map. Orthogonality makes every value a unit vector, but the endpoint degrees are and , impossible. This proves the corresponding Hairy ball theorem obstruction.
There are appropriate extensions rather than an unrestricted integer degree for every pair of manifolds. For a proper map between connected oriented manifolds without boundary of equal dimension, the regular-value count remains finite and is invariant; compactly supported top forms or locally finite homology replace the compact fundamental-class description. Without orientations, degree modulo two counts preimages modulo two and uses mod-two fundamental classes. For manifolds with boundary one uses relative mapping degree for maps of pairs, keeping the boundary away from the chosen target value. Maps of unequal dimensions, or nonproper maps where preimages can escape to infinity, do not in general admit this same signed sheet-count invariant. The central principle is an integer signed count stable under homotopy, with its hypotheses explicitly preserved.