Flux conservation in a superconducting loop Created 2026-09-24 Updated 2026-11-05
An ideal closed loop with negligible resistance can sustain a current that compensates changes in externally linked magnetic flux. In a fixed-geometry circuit model with constant self-inductance , Faraday's law of induction gives , hence remains constant.
The conserved flux includes the loop's self-field. Increasing external flux need not increase the total linked flux: the induced current supplies the compensating contribution. With finite resistance, the circuit equation instead contains , permitting decay and resistive heating.
For an actual superconductor, quantum phase constraints introduce fluxoid and flux quantization in a superconductor. Significant kinetic inductance requires keeping the carrier-motion contribution to the fluxoid; a phase slip can change the winding sector. The simple constant-flux model is therefore a useful idealization with stated circuit assumptions.[ref]
The Feynman Lectures on Physics, Volume III by Richard Feynman and others. §§21-6–21-7: persistent currents, superconducting rings and the distinction from classical infinite conductivity
Start from a gauge-invariant Ginzburg-Landau theory of superconductivity gradient energy , with the coherent pair order parameter and its charge. Varying the free energy with respect to gives the current density displayed in the source. Write to obtainSingle-valuedness around a loop in superconducting material requires . Integrating the current relation therefore gives the exact fluxoid conditionFor a thick ring choose the contour sufficiently deep in the material that the current term is negligible. Then flux itself is approximately quantized, with positive quantumThe sign of the pair charge is absorbed into the orientation of . In a thin ring with appreciable kinetic inductance, it is the fluxoid, not exactly the geometrical flux alone, that remains quantized. A state with nonzero phase-gradient current is a concrete counterexample to dropping the current integral without justification. The flux-only identity thus uses the ordinary thick-ring or negligible-kinetic-inductance limit in addition to phase single-valuedness.