Dissipation range 2026-10-14
The dissipation range contains scales at which kinematic viscosity appreciably affects velocity gradients and converts kinetic energy into heat. In a high-Reynolds-number three-dimensional cascade its characteristic length and time are the Kolmogorov microscales. Intense vortex cores can be intermittent within this range.
Kolmogorov first similarity hypothesis 2026-10-14
In the locally isotropic equilibrium range, the small-scale velocity increment statistics depend on the separation, mean viscous dissipation and kinematic viscosity, independently of large-scale forcing details. Dimensional analysis leaves the Kolmogorov microscales as normalization scales and gives the displayed second-order longitudinal structure function. Universality of is part of the hypothesis, not something proved by dimensional analysis.
Kolmogorov length scale 2026-10-14
The Kolmogorov length scale is the length among the Kolmogorov microscales. Kinematic viscosity and mean energy dissipation per unit mass give the displayed dimensional scale. The associated speed is , so the Reynolds number formed at this length is one.
Ozmidov length 2026-10-14
Equating an inertial eddy turnover time to the inverse buoyancy frequency gives the scale separating buoyancy-affected motions from a smaller approximately isotropic cascade. It is distinct from the viscous Kolmogorov microscales. In very stable local surface-layer scaling it is proportional to the Obukhov length, up to closure constants.
Past exam of the mathematics course of the University of Cambridge 2006 iii Paper 69 4 a Solution Created 2026-10-03 Updated 2026-10-14
Assume statistically steady, three-dimensional turbulence at large Reynolds number, with local statistical homogeneity and statistical isotropy at scales small compared with the forcing scale . The Kolmogorov 1941 theory additionally assumes a local energy cascade, constant mean energy flux per unit mass , and negligible viscous dissipation within the inertial range. Its dimensional form neglects corrections from internal intermittency.
At separation , let be a typical velocity increment. The eddy turnover time is . Constant transfer rate then gives , henceHere is the one-dimensional turbulent energy spectrum, obtained from with . The scaling holds only forThe Kolmogorov length scale follows by setting the scale-dependent Reynolds number to one. The associated Kolmogorov microscales give . At larger scales the forcing matters; at smaller scales kinematic viscosity matters.
Past exam of the mathematics course of the University of Cambridge 2006 iii Paper 79 1 ii Solution Created 2026-10-03 Updated 2026-10-14
Local isotropy of turbulence means that joint small-scale velocity increment statistics are approximately unchanged by rotations, even when the large-scale flow is anisotropic. The universal equilibrium range contains separations much smaller than the integral scale of turbulence: their adjustment times are short compared with the outer eddy turnover time, and their normalized statistics are assumed independent of the detailed large-scale forcing. It includes the inertial range and the dissipation range.
The Kolmogorov first similarity hypothesis says that these locally isotropic statistics depend only on , mean viscous dissipation and kinematic viscosity . Dimensional analysis therefore expresses the second-order longitudinal structure function in terms of the Kolmogorov microscales:The universality of is an assumption of the theory, not a consequence of dimensional analysis alone.
The Kolmogorov second similarity hypothesis removes dependence on kinematic viscosity when . Only and remain, so the Kolmogorov two-thirds law isThe same reasoning gives the predicted order- longitudinal structure function:These are signed moments for integer ; for noninteger orders, use . In particular, the signed third-order coefficient is negative, , in the Kolmogorov four-fifths law.
Past exam of the mathematics course of the University of Cambridge 2006 iii Paper 79 1 i Solution Created 2026-10-03 Updated 2026-10-14
The zeroth law of turbulence states that at fixed outer velocity and integral scale of turbulence , the mean viscous dissipation per unit mass approaches a nonzero finite value as the Reynolds number becomes large. In an established forward energy cascade, this gives , with of order one. The small-scale velocity gradients become large enough to offset decreasing kinematic viscosity; this is the turbulent dissipation anomaly.
At the Kolmogorov microscales, the local Reynolds number is of order one, , and the viscous dissipation is . Solving these balances givesSubstituting the outer-scale estimate, and omitting order-one constants, givesThe associated eddy turnover time is .
Past exam of the mathematics course of the University of Cambridge 2008 iii Paper 87 3 ii Solution Created 2026-10-03 Updated 2026-10-14
The first similarity hypothesis of Kolmogorov 1941 theory states that at sufficiently large Reynolds number, the small-scale statistics in the equilibrium range are locally universal and determined by the mean turbulent kinetic energy dissipation rate and kinematic viscosity , together with the separation or wavenumber being measured. Large-scale forcing details are excluded only at scales well below the integral scale of turbulence.
These parameters define the Kolmogorov microscalesDimensional analysis gives universal functions and withThe dimensional factors follow because has units of velocity squared, whereas has units of velocity squared times length. The universal equilibrium forms include viscous effects; they do not impose a power law through the dissipation range.
The second similarity hypothesis asserts independence of kinematic viscosity at scales large compared with but still small compared with the integral scale. In this inertial range, can depend only on and . Balancing time and length dimensions forces powers and . The same calculation for , using instead of , forces powers and . HenceThe constants and are universal within the hypotheses and the stated normalization. They are related by the exact structure-function spectral filter, rather than by assigning all energy to one sharp scale.
Past exam of the mathematics course of the University of Cambridge 2012 iii Paper 73 1 ii Solution Created 2026-10-03 Updated 2026-10-14
For unforced incompressible flow, multiply the vorticity equation by . The antisymmetric part of the velocity gradient tensor drops out of , leavingStatistical homogeneity removes mean divergences. Integration by parts, together with , givesThe last equality holds for the averages, not pointwise. It follows from the usual curl/divergence identity after the divergence terms have averaged to zero. Vortex stretching produces enstrophy, while viscous diffusion destroys it.
Let , , and use the Kolmogorov microscales and . Since , a slowly changing mean enstrophy has a time derivative of order . The usual small-scale estimate givesThe relative imbalance is consequently , yieldingThe estimate assumes an established high-Reynolds-number cascade and integral-time evolution of the mean, not a rapid initial transient. In a forced flow the exact balance includes ; forcing smooth on the integral scale of turbulence is smaller than the leading small-scale terms.
Past exam of the mathematics course of the University of Cambridge 2012 iii Paper 79 3 iv Solution Created 2026-10-03 Updated 2026-10-14
For very stable continuously turbulent conditions, , local eddies lose leading dependence on their distance from the wall. In very stable surface-layer similarity, the dimensionless functions must therefore scale as and , with positive closure constants. Using givesThus the mean velocity is approximately linear in height and the real buoyancy frequency is approximately constant, . Under the Reynolds analogy, .
The local turbulent kinetic energy balance givesPositive dissipation requires . The turbulent energy-turnover length is of order , hence of order the Obukhov length, independent of observation height. A related buoyancy-limited length is . The Ozmidov length follows by equating an eddy turnover time with :These are turbulent turnover or buoyancy-transition scales. If “the scale at which dissipation occurs” means the actual viscous cutoff, molecular viscosity is also required: the Kolmogorov microscales giveWithout , the viscous length cannot be fixed by the supplied stress and flux alone. Separating it from the turbulent turnover length avoids confusing an energy-budget estimate with the molecular cutoff.
Finally,They become height-independent constants. The commonly used continuation gives and . This numerical value is a closure choice, not a deduction from units; setting would incorrectly leave zero dissipation. Extremely stable intermittent or collapsed turbulence need not satisfy this local-equilibrium model. The relation between the Obukhov and buoyancy-dissipation lengths in the local regime is also analyzed in Grachev and colleagues' similarity study.