Past exam of the mathematics course of the University of Cambridge 2014 iii Paper 35 4 j Solution Created 2026-10-03 Updated 2026-10-06
Fit both the normal and Student t random-effect model with comparable proper prior distributions. Compare priors on the same spread measure: a normal distribution scale is a standard deviation, whereas the standard deviation is .
Use a posterior predictive check: draw study effects and binomial counts from each fitted hierarchy and compare replicated dispersion and extreme study contrasts with the observations. For predicting a new study, generate a new effect from the hierarchy rather than reusing an existing fitted effect. A Leave-one-out cross-validation with entire studies held out can compare integrated predictive probabilities for both arms of each omitted trial, averaging over hyperparameters and its unobserved study effect. Leave-one-study-out influence analysis also reveals whether the difference is driven by a single trial.
Prefer the heavier-tailed hierarchy if it improves the relevant predictive checks and held-out study predictions robustly to reasonable prior choices. The deviance information criterion can supplement the comparison, but its effective parameter count can depend on the latent-variable representation, and six studies give limited information about tail shape. A small numerical criterion difference alone is insufficient evidence.
Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 207 1 e Solution Created 2026-10-03 Updated 2026-10-05
A random-effects meta-analysis allows differences in true treatment effects across countries and eligibility criteria. For trial , let be its estimated log odds ratio and its estimated within-trial variance. A usual approximate statistical model isindependently across trials, with independent of sampling errors. Here is the mean true log odds ratio in the population of comparable trials, and is between-trial heterogeneity, not additional sampling error. Therefore , and for a fitted heterogeneity value,One can estimate by restricted maximum likelihood or another justified method; is a plug-in conditional variance and does not fully account for estimating heterogeneity. With only six studies that uncertainty matters. Different eligibility rules motivate this random effect but do not by themselves establish exchangeability or remove bias; known effect modifiers may warrant stratification or regression.
Use leave-one-study-out influence analysis: fit all six trials, then omit Cohen 1989 and refit both and . Report , the corresponding change in the odds ratio, and changes in the confidence interval and heterogeneity. As a diagnostic with heterogeneity held fixed, writing givesThe fitted Cohen weight would be and . A precise but discordant trial can have large influence; refitting assesses additional influence through heterogeneity. The other five trials' data are absent, so a numerical six-trial influence assessment is not identifiable from the displayed table.