Past exam of the mathematics course of the University of Cambridge 2017 ii Paper 3 23I Solution Created 2026-09-24 Updated 2026-10-05
The length of a curve is . Its arc length parameter is . Regularity gives , so the inverse function theorem gives a smooth inverse and has .
Reparametrize a length minimizer to constant speed on and use the energy functional . By Cauchy-Schwarz inequality, every competitor has , with equality for constant speed, so this parametrization also minimizes . For a fixed-endpoint variation with tangential vector field , differentiation and integration by parts giveThe boundary term is zero. Arbitrary smooth tangential of compact interior support are realizable by the stated variation fact. Taking to be a nonnegative cutoff times proves . Hence a length minimizer is a geodesic after constant-speed reparametrization. The original parameter need not be affine: arbitrary varying-speed parametrizations preserve length but have nonzero covariant acceleration. This qualification is necessary for the literal wording.
For distinct nonantipodal on the punctured unit sphere, there is a unique shorter great circle arc, of length . A minimizing curve exists exactly when that shorter arc avoids the removed north pole. If it avoids the pole it attains the spherical lower bound. If it passes through the pole, arbitrarily small smooth detours have lengths tending to , but equality would force the unique shorter arc, which is unavailable. Thus the infimum is not attained; the longer great circle arc is not a substitute minimizer.
For antipodal in the punctured sphere, one can choose a great circle semicircle avoiding the north pole; it attains length . Thus every admissible antipodal pair has a minimizer. If identical endpoints are included despite the earlier distinctness stipulation, the infimum is zero, but no smooth regular curve attains it; only a nonregular constant curve does.