Level-two open-string polarization decomposition (${\zeta }_{\mu \nu }=\frac{t}{20}(3q_{\mu }{q}_{\nu }+{\eta }_{\mu \nu })+q_{\mu }{A}_{\nu }+q_{\nu }{A}_{\mu }+c_{\mu \nu }$)

For $d=26$, $q^2=-2$ and the physical string state $[{\zeta }_{\mu \nu }{\alpha }_{-1}^{\mu }{\alpha }_{-1}^{\nu }+b_{\mu }{\alpha }_{-2}^{\mu }]|p⟩$, the Virasoro constraints give $b_{\nu }=-q^{\mu }{\zeta }_{\mu \nu }$ and $t={\zeta }^{\mu }{}_{\mu }=-2q\cdot b$. Every solution has the displayed decomposition, where $q\cdot A=0$ and $c$ is symmetric, traceless and transverse to $q$. The vector piece is $L_{-1}(2A\cdot {\alpha }_{-1}|p⟩)$; the scalar piece is $t(L_{-2}+3L_{-1}^2/2)|p⟩/10$. These are null string states, leaving the transverse traceless massive tensor as the physical polarization.