Past exam of the mathematics course of the University of Cambridge 2019 ib Paper 4 19H c Solution Created 2026-09-24 Updated 2026-09-29
Any unbiased linear estimator has the form considered in part (b), and its error is the linear combination of independent normal random variablesThe moment-generating function of a normal distribution therefore gives, for every nonzero real ,Since the exponential function is strictly increasing and , minimizing this exponential moment is exactly the same as minimizing . Part (b) shows that the unique minimizer is . Thus, independently of the sign or magnitude of ,
Past exam of the mathematics course of the University of Cambridge 2020 ia Paper 1 12F b Solution 2026-09-29
The linear combination of independent normal random variables is normal. HenceThis also follows by multiplying the moment-generating functions of the independent and identically distributed random variables.
Past exam of the mathematics course of the University of Cambridge 2021 iii Paper 326 4 2 b Solution 2026-09-29
For every , the continuous linear functional induced by the inner product givesThis is a normal random variable because it is a linear combination of independent normal random variables. Hence the law of is a Gaussian measure. Its mean is zero, and independence together with givesThus its covariance operator of a Gaussian measure is
Past exam of the mathematics course of the University of Cambridge 2021 iii Paper 326 4 3 Solution 2026-09-29
Put . The stated scalar random variable isAs a finite linear combination of independent normal random variables, it is normally distributed. Its mean is zero and its variance is