Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 327 3 Solution Created 2026-10-03 Updated 2026-10-05
Take and the Fourier transform convention . Write the scalar polynomial as , with homogeneous of degree . The principal symbol of the constant-coefficient linear partial differential operator is . It is an elliptic differential operator exactly whenComplex coefficients are allowed, but the frequency is real.
By compactness of the unit sphere, . Homogeneity gives , whereas the lower-degree terms are bounded by for . The triangle inequality then gives the high-frequency lower bound for an elliptic polynomial:for sufficiently large . ThusThe Japanese bracket is . If , a nonzero constant satisfies the same assertion directly.
For real , the Sobolev space is the tempered distribution spaceOne may include in the squared norm for this Fourier transform normalization; it does not change the space. The Local Sobolev space iswhere multiplication of a distribution by a smooth function is followed by extension by zero.
If is a compactly supported distribution, choose a cutoff function equal to one near its compact support. The finite order of a distribution gives an integer and a boundfor a fixed compact set . This also makes a tempered distribution. Its Fourier transform of a compactly supported distribution is the smooth functionThe Leibniz rule gives the last estimate, and parameter differentiation under the finite-order pairing proves smoothness of this Fourier transform. Therefore the negative Sobolev regularity of a compactly supported distribution isIndeed is integrable precisely when . This proves the claimed existence of a sufficiently negative Sobolev space index.
We use three elementary Sobolev space facts: differentiation of order maps continuously into ; for ; and Sobolev multiplication by a smooth cutoff is bounded on for every real . The first two follow directly from the frequency weights. For the third, multiplication of a distribution by a smooth function becomes convolution with the rapidly decaying , andtogether with Young's convolution inequality gives the bound. These facts apply after localization as well.
The high-frequency lower bound for an elliptic polynomial gives a useful global implication. If and , split its Fourier transform into and . The low-frequency part is controlled by , while the high-frequency part is controlled by . Thus, for arbitrary real ,The conclusion that is obtained directly by integrating these frequency bounds; it is not an assumption made to state the estimate.
For the cutoff bootstrap for local elliptic regularity, fix . A cutoff function equal to one near makes a compactly supported distribution after multiplication, so the preceding negative-index argument gives for some finite . Suppose inductively that . For any test function ,The Leibniz rule shows that this commutator has order at most , with smooth functions as coefficients, all with compact support:A second cutoff function equal to one near lets us apply the stated Sobolev space bounds to every term. Hence , while . For , the global estimate yieldsThis holds for every such , so it improves the Local Sobolev space index by one until is reached. A finite number of iterations starting at provesSince was arbitrary, the conclusion holds throughout . For , division by the nonzero constant proves it immediately. This is the asserted elliptic regularity, proved without assuming an initial nonnegative Sobolev space index.
A first-order example on is the first-order Cauchy-Riemann operatorIt is an elliptic differential operator with complex coefficients. In one real variable, is already a first-order elliptic differential operator.
There is no scalar elliptic differential operator of odd order in three variables. If its order were odd, its principal symbol would satisfy on . Regard the continuous mapThe Borsuk-Ulam theorem gives for some . Oddness then gives , contradicting ellipticity. This is the odd-order obstruction for scalar elliptic operators in at least three dimensions; restricting to a three-dimensional subspace proves the higher-dimensional case too. For real coefficients alone, the same obstruction follows from the intermediate value theorem along a path between antipodal points.
The scalar qualification matters. An elliptic system of differential equations can be first order in three variables: with the Pauli matrices, the matrix symbol satisfies and is invertible for . This does not contradict the scalar polynomial obstruction.
Past exam of the mathematics course of the University of Cambridge 2022 iii Paper 327 3 Solution 2026-09-28
The Malgrange–Ehrenpreis theorem states that every nonzero constant-coefficient linear partial differential operator on has a fundamental solution of a linear differential operator: there is an such that .
Write . After an orthogonal change of coordinates and multiplication by a nonzero constant, its polynomial symbol may be written as a monic polynomial in the last frequency,For each real , this polynomial has complex roots counted with multiplicity. Among a fixed finite collection of horizontal lines at bounded heights, one can choose a line that stays a positive distance from all those roots. Continuity of the roots preserves the choice on a neighborhood . Take a countable locally finite cover by such neighborhoods, refine it to a measurable disjoint partition , and let be the chosen height on . The resulting Hörmander staircasehas bounded heights and may be chosen so that on each step.
For a test function , defineThe Paley–Wiener–Schwartz theorem gives rapid decay in the real frequency directions and at most a fixed exponential factor in the bounded imaginary direction. Together with , this proves that the integral defines a continuous distribution. Applying cancels the denominator. The remaining integrand is entire in , so the Cauchy integral theorem shifts every horizontal contour to the real axis; the partition then recombines into . The Fourier inversion theorem giveswhich proves the theorem.
Past exam of the mathematics course of the University of Cambridge 2022 iii Paper 345 1 a Solution 2026-09-28
Let and , so mass conservation for the two-dimensional incompressible flow is automatic. Write for buoyancy and introduce the diffusive operatorsThe Linearized Boussinesq equations areTaking the curl of the momentum conservation equations eliminates the pressure and givesApply and use . Since the constant-coefficient linear partial differential operators commute,This is the viscous-diffusive internal gravity wave equation.