Past exam of the mathematics course of the University of Cambridge 2015 ia Paper 2 7B Solution Created 2026-09-24 Updated 2026-10-06
Work on an interval where the change of variables is smooth and invertible, with . If , the chain rule gives and . Eliminating using the original second-order linear differential equation givesFor the real transformation as printed, take . Set , which is the Liouville transformation of a second-order equation. Differentiating twice makes the coefficient of cancel. Dividing by leavesThe additional term is exactly , as required.
On an interval with , choose and therefore up to a constant. Primes in the following expression mean derivatives with respect to . We have and , giving the WKB correction termNeglecting gives . Since , the WKB approximation isChanging the lower integration limit only rescales the constants. Small is the stated local approximation criterion; rapid variation or a turning point can invalidate it, and small local residual alone need not imply uniform accuracy over an arbitrarily long interval.
The printed hypothesis only says . If real on the interval, the printed square roots require a consistent complex branch. Equivalently a real WKB approximation isThis supplies the oscillatory interpretation for the negative- case instead of silently assuming that the original nonzero hypothesis means positive. Smoothness through the derivatives used above and absence of zeros are required locally.
WKB correction term 2026-10-06
The Liouville transformation of a second-order equation with gives . Neglecting this correction yields amplitude and phase or exponent . Its smallness measures a local slowly-varying-coefficient approximation, away from zeros of .