For and a -representation ,
where .
To prove the formula, write induction as and decompose the -bimodule
For , the map
is a well-defined -equivariant isomorphism. Taking the direct sum over the double cosets proves the result.
For an irreducible -representation , the induced representation is irreducible exactly when, for every nonidentity double coset representative , the restrictions of and its -conjugate to have inner product zero.
This is the finite special-linear-group instance of the general Bruhat decomposition.
For the upper-triangular subgroup of and
the two double cosets are and , and , the diagonal subgroup.
For one-dimensional representations of the upper-triangular subgroup ,
where .
Every linear character of the upper-triangular subgroup with is obtained from a multiplicative character of . Its induction to is irreducible exactly when .

Ancestors (7)

  1. Mackey theory
  2. Induced representation
  3. Representation theory
  4. Algebra
  5. Area of mathematics
  6. Mathematics
  7. Home

Synonyms (3)

Discussion (0) New discussion

There are no discussions about this article yet.

Articles by others on the same topic (0)

There are currently no matching articles.