Matroid greedy algorithm ($w(B)={\sum }_{e\in B}w(e)$)

Assign each element of the finite ground set a real number $w(e)$. The matroid greedy algorithm sorts elements by nonincreasing weight, starts with the empty set, and admits an element exactly when the enlarged selection is a matroid independent set. Ties can be resolved arbitrarily. After all elements have been considered, the result is a matroid basis of maximum total weight among all matroid bases. This holds even with negative weights: the task is to produce a full matroid basis. ^[ref]

Maximizing weight over all matroid independent sets is a different task when weights can be negative. For that task, skip negative elements; zero-weight additions are optional. With weights $w(a)=8$, $w(c)=-1$, $w(b)=-2$ in the weighted three-vector matroid, the heaviest matroid basis is $\{a,c\}$ with weight $7$, while the heaviest matroid independent set is $\{a\}$ with weight $8$. For nonnegative weights, every matroid independent set can be extended to a matroid basis without reducing weight, so the optimum values coincide.

Proof outline. Let $g_1,\dots ,g_r$ be the admitted elements in order, and order any competing matroid basis $b_1,\dots ,b_r$ by nonincreasing weight. If $w(b_k)>w(g_k)$, exchange would let one of $b_1,\dots ,b_k$ augment $\{g_1,\dots ,g_{k-1}\}$. That element was considered before $g_k$ and, by heredity, was admissible even at that earlier stage, a contradiction. Hence $w(g_k)\ge w(b_k)$ for every $k$, and summing proves optimality. Rejected elements remain inadmissible as the selection grows, by heredity, so the final selection is maximal. The guarantee depends on the matroid independence axioms and on weights adding independently across elements; interactions between chosen elements are a different objective.