Suppose decays faster than every power at infinity and, near zero, for every , with strictly increasing and tending to infinity. Subtracting finitely many terms in the integral over gives
The last integral is holomorphic on . These expressions continue the Mellin transform meromorphically to the whole plane, with simple poles precisely at for nonzero .
Strict increase alone does not suffice in the preceding theorem. Let , and , where is continuous, equals one on and vanishes on . After division by the next power, every finite remainder extends continuously to zero. Nevertheless the Mellin transform has genuine poles at accumulating at , so it cannot be a meromorphic function on the whole plane.

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