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The relevant sequence is electron capture followed by nuclear gamma decay:The nuclear spin angular momenta are $0\to 1\to 0$. The captured K-shell electron has total angular momentum $1/2$, so the initial atom-plus-electron system cannot be treated as having zero angular momentum. The atomic vacancy also produces subsequent X-rays or Auger electrons; these are not the selected nuclear transition.

Choose the neutrino momentum along $+z$ and the recoil momentum along $-z$. For a negative-helicity neutrino, $s_{\nu z}=-1/2$. With the two initial electron spin projections, angular momentum conservation allows the daughter to have $m_z=0$ or $+1$. A photon emitted exactly along the recoil direction is transverse, and the $1\to 0$ transition selects the $m_z=+1$ component. Its spin angular momentum points along $+z$, opposite to its momentum.

Thus in the selected collinear geometry the daughter and photon have the same negative helicity as the neutrino, while their spin angular momenta point opposite to the neutrino spin. Reversing all these spin projections gives the positive-helicity alternative. In normalized notation,The actual eigenvalues of $\mathbf{S}\cdot \hat{\mathbf{p}}$ are $\pm 1/2$ for the neutrino and $\pm 1$ for the photon; the equality concerns their normalized signs.