No-cloning theorem for two pure states

No unitary operator

U

can satisfy

U ∣ c_{j} ⟩ ∣0 ⟩ = ∣ c_{j} ⟩ ∣ c_{j} ⟩, j = 0, 1,

for two distinct nonorthogonal pure states. Taking the inner product of these two equations would require

⟨ c_{0} ∣ c_{1} ⟩ = ⟨ c_{0} ∣ c_{1} ⟩^{2},

which is impossible when

0 < ∣ ⟨ c_{0} ∣ c_{1} ⟩ ∣ < 1

.

 Ancestors (5)

 Incoming links (5)

No-cloning theorem
Past exam of the mathematics course of the University of Cambridge / 2018 / ii / Paper 2 / 10D / b / Solution
Past exam of the mathematics course of the University of Cambridge / 2021 / ii / Paper 1 / 10D / b / Solution
Past exam of the mathematics course of the University of Cambridge / 2022 / iii / Paper 323 / 5 / f / Solution
Past exam of the mathematics course of the University of Cambridge / 2026 / iii / Paper 325 / 4 / b / Solution

 View article source

 Discussion (0)

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.

  See all articles in the same topic Create my own version