No positive-Courant cancellation for backward Euler diffusion ($\tau =-(k/2+d^2/12)u_{xxxx}+\cdots$)

For a smooth solution of the heat equation, backward Euler with the centered second difference has residual divided by $k$ equal to $-(k/2+d^2/12)u_{xxxx}+O(k^2+k{d}^2+d^4)$. Both leading terms have the same sign. Under parabolic mesh refinement their coefficient is $-d^2(r/2+1/12)$, which cannot vanish for a positive diffusion Courant number. Consistency of an update $U^{n+1}-U^n=\alpha (r){\delta }^2{U}^{n+1}$ forces $\alpha (r)=r$ for every fixed positive $r$.