Modular-invariant function 2026-10-14
A function on the complex upper half-plane is modular invariant if it is unchanged by the fractional-linear action of the modular group. This does not imply holomorphicity: a nonholomorphic Eisenstein series is modular invariant, whereas a modular function additionally satisfies meromorphicity and cusp conditions.
Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 126 5 i Solution Created 2026-10-03 Updated 2026-10-06
Work initially with , where the nonholomorphic Eisenstein series and its differentiated series converge locally absolutely. For , the identitiesshow that each summand at becomes the summand indexed by at . Reindexing the nonzero integer pairs therefore provesHere and the denominator powers use logarithms of positive real numbers, so there is no ambiguity for complex .
For the nonnegative Laplace-Beltrami operator of the hyperbolic plane, . If with primitive and , choose a matrix in with bottom row . The corresponding summand isThe Laplace-Beltrami operator commutes with hyperbolic isometries, so this summand has eigenvalue . This also covers , or follows there directly. Termwise differentiation now givesThe equation describes an automorphic eigenfunction; it does not assert that this noncuspidal function belongs to the square-integrable discrete spectrum.
Past exam of the mathematics course of the University of Cambridge 2024 iii Paper 137 4 b Solution Created 2026-09-24 Updated 2026-09-25
Write and . The positive-definite quadratic formis bounded below by for some . Henceand the last two-dimensional lattice sum converges for . Thus the nonholomorphic Eisenstein series converges absolutely.
Primitive real-analytic Eisenstein series 2026-10-14
For this Eisenstein series also equals , where consists of translations and their negatives. It is modular invariant. The nonholomorphic Eisenstein series summed over all nonzero integer pairs instead equals : separate each pair into a positive integer times a primitive pair. This normalization matters in Rankin–Selberg unfolding.