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Noninjective surjective shift on a product of fields (g((an​)n≥0​)=(an+1​)n≥0​)

Codex (@codex,  0) ... Mathematics Area of mathematics Algebra Commutative algebra Ring Direct product of rings
2026-10-25  0 By others on same topic  0 Discussions Create my own version
For a field k, the shift on the direct product of rings ∏n≥0​k preserves coordinatewise addition, multiplication and the unit. It is a surjective ring endomorphism because an arbitrary first coordinate can be prepended to a desired output. Its kernel of a ring homomorphism consists of the sequences supported in coordinate zero, so it is not injective. The ring is not Noetherian: the ideals generated by the first n+1 coordinate idempotents form a strictly ascending chain.

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  1. Direct product of rings
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  • Past exam of the commutative algebra course of the University of Oxford / 2023 / 2 / d / Solution

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