Past exam of the mathematics course of the University of Cambridge 2001 iii Paper 52 1 b Solution Created 2026-10-03 Updated 2026-10-14
For the adult-survival annual pulse-breeding predator-prey model, a positive annual fixed point exists when and :At this point the Jacobian matrix isIf , the two eigenvalues are a complex conjugate pair of moduli one. The annual samples show linearly neutral seasonal oscillations. If , they form a reciprocal negative real pair and the fixed point is a saddle fixed point of a map. Equality at four is a degenerate boundary needing nonlinear analysis. For replacement rather than surviving adults the same calculation gives trace and determinant one.
The absence of an attracting annual cycle is stronger than a linear observation. Put , . The update becomesIt is the composition of two nonlinear shear maps, each of determinant one: an area-preserving seasonal predator-prey map. No isolated positive periodic orbit has an open attracting basin. Neutral linear oscillations alone also do not prove nonlinear stability at every resonance. In particular, this density-independent model does not select an asymptotically stable oscillation amplitude.
The Nicholson-Bailey model instead counts parasitoid offspring from attacked hosts:Its positive equilibrium has and . Its Jacobian matrix hasSince the determinant exceeds one while the positive trace is below two, the eigenvalues are complex with moduli greater than one: instability of the Nicholson-Bailey equilibrium produces outward oscillations near it. The two maps share an exponential prey-survival factor but have different reproduction laws and stability properties.
