One-loop running of the strong coupling (${\alpha }_s(\mu )=4\pi /[{\beta }_0\ln ({\mu }^2/{\Lambda }^2)]$)

With ${\beta }_0>0$, differentiating ${\alpha }_s=g^2/(4\pi )$ under $\mu dg/d\mu =-{\beta }_0{g}^3/(16{\pi }^2)$ gives $d(1/{\alpha }_s)/d\ln \mu ={\beta }_0/(2\pi )$. Integration defines the strong-coupling scale $\Lambda$ and gives the displayed positive branch for $\mu >\Lambda$. The pole signals breakdown of perturbative quantum field theory. The equivalence between specifying ${\alpha }_s$ and specifying $\Lambda$ is dimensional transmutation.

For positive ${\beta }_0$, the one-loop running coupling tends to zero at high energy and grows as energy decreases. Near the strong-coupling scale, omitted perturbative terms cease to be small; the apparent infrared pole is not a controlled prediction of a physical infinity. Continuing the algebraic formula below $\Lambda$ gives a negative coupling and is not a valid physical continuation. Confinement and hadron formation are nonperturbative phenomena, not a theorem proved by this one-loop pole. The integration constant obeys $\Lambda ={\mu }_0\exp [-1/(2{\beta }_0{\alpha }_0)]$, so an order-one coefficient alone cannot determine an absolute mass scale; a reference coupling or empirical input is also necessary.

At a heavy-quark mass $m$, leading-order continuity gives ${\beta }_{-}\ln (m/{\Lambda }_{-})={\beta }_{+}\ln (m/{\Lambda }_{+})$. Therefore $\boxed{{\Lambda }_{+}=m({\Lambda }_{-}/m{)}^{{\beta }_{-}/{\beta }_{+}}}$. This is a change of the strong-coupling scale parametrization across a change of active flavour number, not a discontinuity of the matched QCD coupling. For four to five active flavours in $SU(3)$, ${\beta }_{-}=25/3$ and ${\beta }_{+}=23/3$, hence ${\Lambda }_5={\Lambda }_4(m_b/{\Lambda }_4{)}^{-2/23}$.