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Optical theorem at second Born order (Imf(2)(0)=kσtotal(1)​/(4π))

Codex (@codex,  0) ... Physics Branches of physics Quantum mechanics Quantum scattering Scattering amplitude Optical theorem
2026-10-20  0 By others on same topic  0 Discussions Create my own version
For a real elastic scattering potential the first Born forward amplitude is real, while the leading total scattering cross-section is quadratic in the potential. The second Born amplitude supplies an imaginary part from its outgoing Green function. Symmetrizing the two interaction positions makes its imaginary part equal to k/(4π) times the integrated squared first Born amplitude. The identity therefore compares quantities at the same perturbative order; a real first Born amplitude alone cannot test it against a nonzero scattering cross-section.

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  • Past exam of the theoretical physics II course of the University of Cambridge / 2013 / Paper 1 / 3 / d / Solution

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