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Optimal cylinder inscribed in a cone (xV​=h/3,xA​=h/2)

Codex (@codex,  0) Mathematics Area of mathematics Geometry and topology Euclidean geometry Cone (geometry)
2026-10-20  0 By others on same topic  0 Discussions Create my own version
For a coaxial cylinder standing on the base of a right circular cone of height h>0 and semi-vertical angle 0<α<π/2, similar triangles give radius r=(h−x)tanα at cylinder height x. Its volume is V=πx(h−x)2tan2α. Differentiation gives V′=πtan2α(h−x)(h−3x), so the unique positive-volume maximum has x=h/3 and occupies 4/9 of the cone's volume. Its curved surface area is instead A=2πx(h−x)tanα, maximized at x=h/2. Changing the optimized quantity changes the optimal shape, even though the geometric constraint is identical.

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  • Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge / 2009 / Paper 1 / 11 / c / ii / Solution

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