The generating function gives , so the odd function is orthogonal to every even-degree Legendre polynomial. For , integrate the self-adjoint form of the Legendre differential equation from zero to one:Thus . Differentiating the generating function in and then setting givesCombining these identities with the normalization of yieldsFor the Legendre expansion of the sign function, , so the Parseval identity givesTherefore the requested sum equals
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