Past exam of the chemistry course of the year 1 of the natural sciences course of the University of Cambridge / 2024 / Paper 1 / 4 / c / i

Convert the supplied concentrations to $[\mathrm{NO}]=1.00\times 10^{-7}\mathrm{M}$ and $[{\mathrm{O}}_2]=3.00\times 10^{-5}\mathrm{M}$. ThenThe combined loss coefficient is $6600{\mathrm{s}}^{-1}$. Neglecting the smaller NO-dependent loss would give $8.72\times 10^{-14}\mathrm{M}$, a close low-NO approximation, but the full expression is just as easy to evaluate.