Past exam of the collisionless plasma physics course of the University of Oxford / 2025 / 2 / b

Table of contents
- Solution b

Solution

A wave turning point satisfies

k^{2} (x) = 0

, equivalently

ω_{p e}^{2} (x) = ω^{2}

. Therefore

x = \pm x_{T}, x_{T} = L 1 - \frac{ω ^{2}}{ω _{p e 0}^{2}} .

For

0 < ω < ω_{p e 0}

the two wave turning points lie inside the column and are simple. Defining

a = - x_{T}

and

b = x_{T}

, the local dispersion relation becomes

k^{2} (x) = \frac{ω _{p e 0}^{2}}{c ^{2} L ^{2}} (x^{2} - x_{T}^{2}) .

 Ancestors (11)

 View article source

 Discussion (0)

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.

  See all articles in the same topic Create my own version