Past exam of the computer science course of the University of Oxford / 2022 / Quantum information / 3 / b / ii / Solution

Since $H=(X+Z)/\sqrt{2}$, the Hadamard gate is, up to a global phase, the rotation gateThus its Bloch sphere action is a rotation through $\pi$ about the axis $(1,0,1)/\sqrt{2}$, halfway between the positive $x$ and $z$ axes:The identities $HXH=Z$, $HYH=-Y$ and $HZH=X$ verify this Bloch vector transformation directly.