The vectors from the B atom to its three nearest N neighbours can be chosen as
Indeed , and . All three have length . Repeating the two-site basis over produces the honeycomb pattern in the first panel of the original figure in solution.
Solving gives
The first Brillouin zone is the Wigner–Seitz hexagon of this reciprocal lattice. Its vertices are and , with independent signs in the latter set. The centre is ; one inequivalent corner is , with . Corners related by a reciprocal lattice translation are equivalent, leaving two inequivalent valleys.
At a valley , . For h-BN the inequivalent sublattice energies therefore leave the direct two-band gap
Graphene's equivalent carbon sites instead have in this model, so the two bands touch at the valleys. Near a valley, : graphene has approximately linear, gapless Dirac cones while h-BN has gapped band edges. The model panel in the original figure in solution displays this distinction.
First, undoped h-BN is an electrical insulator with thermally suppressed carriers, whereas neutral graphene is a zero-gap semimetal whose transport is readily changed by gating. Disorder, temperature and contacts still affect its measured conductivity. Second, h-BN suppresses interband absorption below its large gap and is transparent over much of the visible range, whereas graphene permits low-energy interband absorption unless occupations block it. A quantitative optical threshold in real h-BN also involves additional bands and strong excitonic effects; a two-orbital model should not be presented as a numerical prediction of its complete optical spectrum.