Past exam of the differential equations 1 course of the University of Oxford / 2021 / 3 / b / ii

Applying time reversal of an autonomous differential equation to the system from part (i), and renaming its coordinates $(x,y)$, givesThe equilibrium points remain $(1,-1)$ and $(-1,-1)$. Time reversal of an autonomous differential equation preserves a saddle equilibrium, interchanging its stable and unstable directions; it also reverses the direction around a centre equilibrium. Therefore this system has precisely the required counterclockwise centre at $(1,-1)$ and saddle at $(-1,-1)$.