Write for the red-blue finite colouring of unordered pairs. The two alternatives concern one arithmetic progression or a pair of disjoint arithmetic progressions; they need not be mutually exclusive. For , a singleton already has no non-blue edge, so the first alternative holds. Assume henceforth .
If the first alternative fails, every -term arithmetic progression contains a red pair. Label each by one such pair's positions , choosing the first in a fixed ordering when there are several. This is a finite colouring with at most colours. The following two branches establish the arithmetic-progression bipartite Ramsey dichotomy.
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