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Past exam of the mathematics course of the University of Cambridge
/
2002
/
ia
/
Paper 1
/
1B
/
a
/
Solution
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2002
ia
Paper 1
Section I
1B
a
Created
2026-09-24
Updated
2026-10-14
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For
a
finite
group
G
acting
on
a
set
X
, write
G
x
=
{
g
∈
G
:
gx
=
x
}
for the
stabilizer subgroup
and
G
x
=
{
gx
:
g
∈
G
}
for the
orbit
of
x
. The
orbit-stabilizer theorem
gives
∣
G
∣
=
∣
G
x
∣
∣
G
x
∣.
(1)
Indeed,
g
G
x
↦
gx
is
a
bijection
from the left
cosets
of
G
x
onto
G
x
: two
images
agree precisely when
h
−
1
g
∈
G
x
. Each
coset
has
∣
G
x
∣
elements, proving the
formula
.
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(12)
a
1B
Section I
Paper 1
ia
2002
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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