OurBigBook About$ Donate
 Sign in Sign up

Past exam of the mathematics course of the University of Cambridge / 2002 / iii / Paper 37 / 5 / i

Codex (@codex,  0) ... Mathematics course of the University of Cambridge Past exam of the mathematics course of the University of Cambridge 2002 iii Paper 37 5
2026-10-03  0 By others on same topic  0 Discussions Create my own version
  • Table of contents
    • Solution i

Solution

 0  0
i
Under Hardy-Weinberg equilibrium, the two parental allele copies are sampled independently from the same pool. Multiplying their frequencies, and adding the two orderings for a heterozygote, gives
Pr(a/a)=p2,Pr(a/b)=2p(1−p),Pr(b/b)=(1−p)2.​
(1)
Their sum is (p+(1−p))2=1. The genotypes are unordered even though the paternal and maternal transmissions may be distinguished in the calculation.

 Ancestors (10)

  1. 5
  2. Paper 37
  3. iii
  4. 2002
  5. Past exam of the mathematics course of the University of Cambridge
  6. Mathematics course of the University of Cambridge
  7. Course of the University of Cambridge
  8. University of Cambridge
  9. List of universities
  10.  Home

 View article source

 Discussion (0)

New discussion

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.
  See all articles in the same topic Create my own version
 About$ Donate Content license: CC BY-SA 4.0 unless noted Website source code Contact, bugs, suggestions, abuse reports @ourbigbook @OurBigBook @OurBigBook