Choose the extended supersymmetry normalization
The central charge in supersymmetry is antisymmetric in , because the full anticommutator is symmetric and is antisymmetric. In a massive one-particle state rest frame, , and the first anticommutator becomes .
A unitary skew-diagonalization of an antisymmetric matrix puts into blocks , with a remaining zero direction if is odd. For one block write , and label its two supersymmetries . The combinations
have
For example the mixed contribution to the first expression is . This is the phase-aligned version of taking a supercharge minus a unitary combination of its adjoints, as suggested by the hint.
For every operator and normalized state ,
Applying this to in every block proves the BPS bound
If the algebra is instead written with on its right side, the same result is ; the factor is purely a central-charge convention.
A BPS state saturates at least one of these inequalities. The corresponding zero-norm combinations of supercharges and their adjoints annihilate the representation, so part of supersymmetry is preserved. Its massive supermultiplet is shortened: each saturated block removes two complex fermionic oscillators, giving states from a spin- Clifford vacuum when blocks saturate, before any necessary CPT completion of a supermultiplet. It preserves of the real supercharges. Its mass is tied to the central charges in supersymmetry and remains protected while it stays on the same short branch. Stability is not unconditional: a wall of marginal stability can permit a charged BPS state to decay into other BPS states with the same total charge.
At fixed nonzero four-momentum, take the finite physical supermultiplet and write for fermion parity. Each supercharge is odd, so and the same holds for its adjoint. By the cyclic property of the trace,
Consequently . Sum the two spinor components of the Super-Poincaré algebra. Since , their sum is . On a fixed-energy representation, , yielding
For a nonzero physical one-particle momentum, , including the massless case. Hence the bosonic and fermionic physical state counts agree:
Equivalently a nonzero normalized supercharge and its adjoint define an odd involution pairing the two subspaces. This is supertrace pairing at positive energy; it counts spin polarizations, not merely distinct names of particles.
The phrase “every supermultiplet” requires this positive-energy qualification. A zero-energy supersymmetric vacuum with all supercharges acting as zero is a one-dimensional bosonic representation with no fermionic partner. It is a counterexample to the unrestricted statement, because division by is then impossible. It does not contradict the requested equality for particle supermultiplets.
Sum the diagonal spinor entries of the Super-Poincaré algebra, obtaining
The expectation in any state is therefore
This proves energy positivity in global supersymmetry, with the energy origin fixed by the algebra.
If a ground state is invariant under supersymmetry, all its supercharge variations vanish and its energy is zero. Conversely, zero energy makes every nonnegative squared norm above zero, so every supercharge annihilates that vacuum. Thus strictly positive vacuum energy implies supersymmetry breaking: some supercharge fails to annihilate the vacuum. A finite-volume regulator can be used before passing to vacuum-energy density. This is a statement about the global supersymmetry algebra; it is not a positivity theorem for the general supergravity F-term potential.

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