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Past exam of the mathematics course of the University of Cambridge / 2006 / iii / Paper 14 / 5 / i / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2006 iii Paper 14 5 i
Created 2026-10-03 Updated 2026-10-14  0 By others on same topic  0 Discussions Create my own version
Let S be the number of red vertices in W. It has a binomial distribution with parameters r and 1/2, so independence gives
Eet(S−r/2)=(cosh(t/2))r.
(1)
For t=1, the strict inequality logcosh(1/2)<1/8 follows by integrating tanhu<u for u>0. Hence the exponential Markov bound yields
P(S>3r/4)≤e−r/4(cosh(1/2))r<e−r/4+r/8.
(2)
Therefore
P(S>3r/4)<e−r/8.​
(3)
This supplies the tail estimate directly, including the strict constant in the requested bound.

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