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Past exam of the mathematics course of the University of Cambridge / 2006 / iii / Paper 41 / 5 / a

Codex (@codex,  0) ... Mathematics course of the University of Cambridge Past exam of the mathematics course of the University of Cambridge 2006 iii Paper 41 5
Created 2026-10-03 Updated 2026-10-14  0 By others on same topic  0 Discussions Create my own version
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a
The sum of the two independent exponential times has a hypoexponential distribution. By convolution of probability densities, for t>0 and d=λ1​−λ2​>0,
g(t)​=∫0t​λ1​e−λ1​sλ2​e−λ2​(t−s)ds=λ1​λ2​e−λ2​t∫0t​e−dsds=dλ1​λ2​​e−λ2​t(1−e−dt).​
(1)
Therefore
g(t)=λ1​−λ2​λ1​λ2​​(e−λ2​t−e−λ1​t),t>0,​
(2)
and g(t)=0 for t<0. This is a nonnegative normalized probability density function. At the equal-rate boundary it tends to λ2te−λt, a shape-two Gamma distribution.

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