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Past exam of the mathematics course of the University of Cambridge / 2008 / iii / Paper 73 / 2 / i / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2008 iii Paper 73 2 i
Created 2026-10-03 Updated 2026-10-14  0 By others on same topic  0 Discussions Create my own version
Divide the Friedmann equation by a2 and use a=(1+z)−1. The Hubble parameter therefore satisfies
H0​H(z)​=Ωm,0​(1+z)3+ΩΛ,0​​.​
(1)
The positive root describes the expanding branch. Spatial flatness and the neglect of radiation in cosmology imply Ωm,0​+ΩΛ,0​=1.

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