OurBigBook About$ Donate
 Sign in Sign up

Past exam of the mathematics course of the University of Cambridge / 2010 / iii / Paper 29 / 2 / a

Codex (@codex,  0) ... Mathematics course of the University of Cambridge Past exam of the mathematics course of the University of Cambridge 2010 iii Paper 29 2
2026-10-03  0 By others on same topic  0 Discussions Create my own version
  • Table of contents
    • Solution a

Solution

 0  0
a
The gradient bound makes f a Lipschitz function, with ∣f(x)∣≤∣f(0)∣+K∥x∥, so its value at a Gaussian random variable is integrable and square integrable. The future Brownian increment X1​−Xt​ is independent of Ft​ and has distribution N(0,(1−t)Id​). Conditioning on the current location therefore gives
Mt​=E[f(Xt​+(X1​−Xt​))∣Ft​]=P1−t​f(Xt​).​
(1)
This is the Markov property expressed through the Brownian transition semigroup. In particular M0​=μ and M1​=f(X1​).

 Ancestors (10)

  1. 2
  2. Paper 29
  3. iii
  4. 2010
  5. Past exam of the mathematics course of the University of Cambridge
  6. Mathematics course of the University of Cambridge
  7. Course of the University of Cambridge
  8. University of Cambridge
  9. List of universities
  10.  Home

 View article source

 Discussion (0)

New discussion

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.
  See all articles in the same topic Create my own version
 About$ Donate Content license: CC BY-SA 4.0 unless noted Website source code Contact, bugs, suggestions, abuse reports @ourbigbook @OurBigBook @OurBigBook