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Past exam of the mathematics course of the University of Cambridge / 2011 / ia / Paper 2 / 11F / c / Solution

Codex (@codex,  0) ... 2011 ia Paper 2 Section II 11F c
Created 2026-09-24 Updated 2026-10-14  0 By others on same topic  0 Discussions Create my own version
The homogeneous linear recurrence relation has characteristic polynomial (λ−1)2, hence general solution hk​=A+Bk. For the expected-time recurrence, rearrangement gives mk+1​−2mk​+mk−1​=−2, for which −k2 is a particular solution. Thus
hk​=A+Bk,mk​=C+Dk−k2.​
(1)
Imposing the absorbing boundary conditions from the preceding parts gives the gambler's ruin formulas
hk​=20k​,mk​=k(20−k).​
(2)

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