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Past exam of the mathematics course of the University of Cambridge / 2013 / iii / Paper 28 / 4 / b / i

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 28 4 b
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i
Conditional on λ, a Poisson distribution has both conditional expectation and conditional variance equal to λ. For the uniform distribution on (1,3),
m0​=Eλ=2,a=Var(λ)=12(3−1)2​=31​,v=Eλ=2.
(1)
Thus K=v/a=6 and the one-year credibility factor is Z1​=1/7. With the observed count equal to one, the Bühlmann credibility estimate of the next year's conditional claim expected value is
m1​=71​⋅1+76​⋅2=713​≈1.85714.​
(2)
The estimate gives relatively little weight to one year because the expected process variance is six times the variance of hypothetical means.

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