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Past exam of the mathematics course of the University of Cambridge / 2014 / ia / Paper 1 / 8C / iv / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2014 ia Paper 1 8C iv
Created 2026-09-24 Updated 2026-10-06  0 By others on same topic  0 Discussions Create my own version
Every traceless skew-Hermitian matrix of size two has the form
C=(ip−w​w−ip​),p∈R,
(1)
so it equals M(c) for c=(2p,2Rew,2Imw). If c=0, take A=B=0. Otherwise choose a unit vector u perpendicular to c and set a=u, b=c×u. The vector triple product gives a×b=c.
By part (iii), choosing A=M(a) and B=M(b) gives the required representation
C=[A,B].​
(2)
In fact both factors can themselves be chosen as traceless skew-Hermitian matrices. The cross-product model of su(2) explains this geometric commutator construction.

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