Insert an exact smooth solution into the linear multistep method and define its unscaled local truncation error byIts Taylor expansion has coefficientsThe method has order at least exactly when , since then for every sufficiently smooth . Necessity can be checked by inserting polynomials of successive degrees. This also corresponds to the usual truncation error .
On the other hand, expansion of the characteristic polynomials of a linear multistep method givesThus the exponential-symbol order criterion for a multistep method isIf “order ” is meant to be the exact rather than guaranteed order, one additionally requires . The first two vanishing conditions are the usual consistency of a numerical method relations , .
The relevant one of the characteristic polynomials of a linear multistep method isThe coefficients on the right are chosen to give third order, so consistency of a numerical method is already available. By the Dahlquist equivalence theorem, convergence with convergent starting values is equivalent to zero-stability: every root of must satisfy , and every root on the unit circle must be simple.
If , the quadratic is negative at and tends to as , so it has a root less than . If , its root product is , so at least one root has modulus greater than one. For , its real roots lie in . For , its conjugate roots have modulus .
At , the three roots are , with the unit-modulus roots simple. At , they are , again simple. The repeated quadratic root at is , strictly inside the unit circle, which the root condition for a multistep method permits. ThereforeThis is the root stability of a cubic multistep polynomial; oscillatory parasitic roots at the endpoints do not invalidate convergence when their starting amplitudes tend to zero.
Articles by others on the same topic
There are currently no matching articles.