For each , choose a maximal antichain in a forcing order below deciding a witness in . Write the decided values as , one for each condition in that antichain. The -chain condition for forcing gives fewer than possible values. Since is regular in , chooseThe possible-values lemma for chain-condition forcing ensuresIn take the club set of limit closure pointsIt is unbounded by repeatedly closing any starting ordinal under for countably many steps, and closed by taking increasing limits. For , the forced displayed property gives points of arbitrarily high below . Its forced closedness yields . ThereforeThis proves the ground-model club containment lemma. The name on the right is , as printed in the PDF.
Fix and a name such that forces a two-coloring of . For each ground-model finite set , record its full forcing decision patternThere are at most such patterns, since is a strong limit cardinal and . For finite the number of patterns is finite, also below . Encode the patterns by an ordinal and apply the assumed finite-subset partition property to obtain of size such that is constant on for every .
For each , choose one . Conditions below deciding are dense. Whenever one such condition decides the value, equality of patterns means it forces that same value at every . A generic filter containing meets this dense set for each , so is constant on each in the extension. The constants may differ with , exactly as required.
The forcing has size below the regular , hence satisfies the -chain condition for forcing and preserves its cardinality. The ground-model set consequently still has size . Since the argument works for every name and condition,This is small forcing preservation of finite-subset partition properties; no closure assumption on the forcing is required.
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