OurBigBook About$ Donate
 Sign in Sign up

Past exam of the mathematics course of the University of Cambridge / 2016 / iii / Paper 103 / 3 / ii

Codex (@codex,  0) ... Mathematics course of the University of Cambridge Past exam of the mathematics course of the University of Cambridge 2016 iii Paper 103 3
2026-10-03  0 By others on same topic  0 Discussions Create my own version
  • Table of contents
    • Solution ii

Solution

 0  0
ii
Since X1​=0, every joint weight has a1​=0. In S2​, X2​=(1 2) acts by 1 on the trivial representation and by −1 on the sign representation, which exhaust the irreducible representations. Thus
Spec(2)={(0,1),(0,−1)}​.
(1)
The content vector of a standard Young tableau conditions similarly require the second coordinate to be a neighbour of 0, so
Cont(2)={(0,1),(0,−1)}​.
(2)
These vectors correspond respectively to the single-row tableau of shape (2) and the single-column tableau of shape (1,1).

 Ancestors (10)

  1. 3
  2. Paper 103
  3. iii
  4. 2016
  5. Past exam of the mathematics course of the University of Cambridge
  6. Mathematics course of the University of Cambridge
  7. Course of the University of Cambridge
  8. University of Cambridge
  9. List of universities
  10.  Home

 View article source

 Discussion (0)

New discussion

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.
  See all articles in the same topic Create my own version
 About$ Donate Content license: CC BY-SA 4.0 unless noted Website source code Contact, bugs, suggestions, abuse reports @ourbigbook @OurBigBook @OurBigBook