For an integer , the Sobolev space iswhere is a weak derivative. For one may use the Sobolev norm ; for use the maximum of the finitely many essential-supremum norms.
For , the Sobolev inequality is , with Sobolev conjugate exponent . For , Morrey's inequality supplies a continuous representative satisfyingAt the representative is Lipschitz continuous. At the critical exponent , first-order Sobolev regularity gives every finite embedding for , with an inhomogeneous norm, but generally no embedding. The one-dimensional endpoint is an exception.
For the proof of Morrey's inequality, start with a smooth and write for its average on a ball. Averaging the fundamental theorem of calculus along a line segment and changing radial variables givesThe last step is the Holder inequality; integrability of the kernel to power is exactly . For , translate the averaging ball along the segment from to . The fundamental theorem of calculus along a line segment and the Holder inequality giveCombining the two point-to-average bounds and this average-to-average bound proves the required Hölder estimate. The point-to-average bound with , together with , gives the supremum estimate. Density of smooth functions in a Sobolev space then gives a uniformly convergent sequence of smooth representatives, preserving both bounds. For , mollification gives the Lipschitz version.
For the decay conclusion assume . The representative is uniformly continuous. If along points escaping to infinity, the Hölder bound gives a radius , independent of , on which . A subsequence has disjoint radius- balls, each contributing at least to , a contradiction. This is uniformly continuous integrable functions vanish at infinity.
The finite- restriction is necessary. If the printed range includes , its decay assertion is false: belongs to but does not tend to zero.
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