Choose a countable dense subset of the normed vector space . For each fixed , the scalar sequence is bounded becauseRepeated use of the Bolzano-Weierstrass theorem followed by a diagonal subsequence argument produces a subsequence for which converges for every .
Let be the linear span of the . On every , defineFinite linear combinations show that is linear, and passage to the limit in gives . Thus is a bounded linear functional on the dense linear subspace and extends uniquely to an element of the dual space with .
For arbitrary and ,First choose close to , then let tend to infinity. This provesThis is the Sequential Banach-Alaoglu theorem for a separable predual.
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