OurBigBook About$ Donate
 Sign in Sign up

Past exam of the mathematics course of the University of Cambridge / 2018 / iii / Paper 140 / 2 / a / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 140 2 a
Created 2026-10-03 Updated 2026-10-05  0 By others on same topic  0 Discussions Create my own version
Let dimV=2n and let V+​=ker(S−I) and V−​=ker(S+I) be the two eigenspaces. The involution identity gives a direct sum, since
v=2v+Sv​+2v−Sv​,V=V+​⊕V−​.
(1)
For u,v in either one of these eigenspaces, the anti-symplectic involution identity implies
Ω(u,v)=Ω(Su,Sv)=−Ω(u,v),
(2)
so both are isotropic subspaces of a symplectic vector space. Such a subspace has dimension at most n: W⊂WΩ and the nondegenerate bilinear form Ω gives dimWΩ=2n−dimW, where WΩ is the symplectic orthogonal complement. As their dimensions add to 2n, both have dimension n. Therefore
Fix(S)=V+​ is a Lagrangian subspace.​
(3)

 Ancestors (11)

  1. a
  2. 2
  3. Paper 140
  4. iii
  5. 2018
  6. Past exam of the mathematics course of the University of Cambridge
  7. Mathematics course of the University of Cambridge
  8. Course of the University of Cambridge
  9. University of Cambridge
  10. List of universities
  11.  Home

 View article source

 Discussion (0)

New discussion

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.
  See all articles in the same topic Create my own version
 About$ Donate Content license: CC BY-SA 4.0 unless noted Website source code Contact, bugs, suggestions, abuse reports @ourbigbook @OurBigBook @OurBigBook