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Past exam of the mathematics course of the University of Cambridge / 2018 / iii / Paper 141 / 2 / b / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 141 2 b
Created 2026-10-03 Updated 2026-10-05  0 By others on same topic  0 Discussions Create my own version
Insert a kink on any component of an oriented link diagram for L. Switching the kink's crossing gives another link diagram of L; its oriented smoothing separates off a small unknot in a ball disjoint from the rest of L. The skein relation therefore gives
(q−q−1)V(L)=(q1/2−q−1/2)V(L⨿U1​).
(1)
Cancel the nonzero factor q1/2−q−1/2 in the Laurent polynomial ring to obtain
V(L⨿U1​)=(q1/2+q−1/2)V(L)=V(U2​)V(L).​
(2)

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