Using the Levi-Civita symbol and the epsilon-delta identity,
This proves the vector triple product identity
Applying it inside the scalar triple product gives Lagrange's identity
The vector triple product identity gives
Taking the dot product with therefore yields
Write
The first equation is then automatic, while the second becomes
Thus the general solution is
As varies, and are antipodal points of the sphere with center and radius , so they are opposite ends of a diameter.
Let the vertex position vectors be . Suppose
Subtracting the second scalar product from the first gives
so the remaining pair of opposite edges of a tetrahedron is also perpendicular.
Put
Direct expansion gives, cyclically,
with the other two differences equal to minus twice the scalar products of the other opposite-edge pairs. All three scalar products vanish, hence

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