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Past exam of the mathematics course of the University of Cambridge / 2019 / ib / Paper 4 / 6B / b / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2019 ib Paper 4 6B b
Created 2026-09-24 Updated 2026-09-29  0 By others on same topic  0 Discussions Create my own version
The momentum operator in the position representation is p​=−iℏd/dx. Differentiating the given Gaussian wave packet gives
dxdΨ​=(−2αx+ik)Ψ,Ψ∗p​Ψ=(2iℏαx+ℏk)∣Ψ∣2.
(1)
The probability density ∣Ψ∣2 is an even function, so the term proportional to the odd function x has integral zero. Normalization supplies ∫−∞∞​∣Ψ∣2dx=1, and hence
⟨p⟩=∫−∞∞​Ψ∗p​Ψdx=ℏk​.
(2)

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