Choose with . Conjugation by identifieswithIt follows that the unit-vector stabilizer in a special orthogonal group is an embedded submanifold diffeomorphic to , andAt , its tangent space is
For any , both and contain the identity. At the identity,Identify with the exterior square . The orthogonal complement of is . If and are linearly independent, the nonzero bivector belongs to the orthogonal complements of both tangent spaces. Their sum is therefore a proper subspace of , so the intersection is not transverse. If , then , whose tangent space is proper, so they are again not transverse. Consequentlyas summarized by distinct unit-vector stabilizers are not transverse.
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